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2z^2+18z+28=0
a = 2; b = 18; c = +28;
Δ = b2-4ac
Δ = 182-4·2·28
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-10}{2*2}=\frac{-28}{4} =-7 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+10}{2*2}=\frac{-8}{4} =-2 $
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